Question 91
The sum of the ages of father and son at present is 33. Two years ago the product of their ages was 28. What is the age of the father and the son?
Solution
Let the age of son = $$x$$ years and father's age = $$(33-x)$$ years
Product of their ages 2 years ago = $$(x-2)(33-x-2) = 28$$
=> $$(x-2)(31-x)=28$$
=> $$31x-x^2-62+2x=28$$
=> $$x^2-33x+90=0$$
=> $$x^2-3x-30x+90=0$$
=> $$x(x-3)-30(x-3)=0$$
=> $$(x-3)(x-30)=0$$
=> $$x=30,3$$
$$\therefore$$ Ages of father and son are 30 and 3
=> Ans - (B)
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