Question 91

The sum of the ages of father and son at present is 33. Two years ago the product of their ages was 28. What is the age of the father and the son?

Solution

Let the age of son = $$x$$ years and father's age = $$(33-x)$$ years

Product of their ages 2 years ago = $$(x-2)(33-x-2) = 28$$

=> $$(x-2)(31-x)=28$$

=> $$31x-x^2-62+2x=28$$

=> $$x^2-33x+90=0$$

=> $$x^2-3x-30x+90=0$$

=> $$x(x-3)-30(x-3)=0$$

=> $$(x-3)(x-30)=0$$

=> $$x=30,3$$

$$\therefore$$ Ages of father and son are 30 and 3

=> Ans - (B)

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