Question 90

In ΔPQR, ∠QPR = 45° and the bisectors of ∠PQR and ∠PRQ meets at O. What is the value (in degrees) of ∠QOR?

Solution

Given : O is the incentre of $$\triangle$$ PQR and $$\angle$$ QPR = 45°

To find : $$\angle$$ QOR = $$\theta$$ = ?

Incentre of a triangle = $$90^\circ+\frac{1}{2} \times $$ (Angle opposite to it)

=> $$\theta=90^\circ+\frac{45^\circ}{2}$$

=> $$\theta=90^\circ+22.5^\circ$$

=> $$\theta=112.5^\circ$$

=> Ans - (B)

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