Question 9

If 5 + 3 + 1 = 15 and 6 + 1 + 4 = 24, then 4 + 3 + 0 = ?

Given : 5 + 3 + 1 = 15 and 6 + 1 + 4 = 24

If we replace '+' with 'x', then L.H.S. = R.H.S.

Eg :- $$5\times3\times1=15$$

and $$6\times1\times4=24$$

Similarly, $$4\times3\times0=0$$

=> Ans - (C)

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