Given that $$P\left(A\right) = 1/3, P\left(B\right) = 1/4, P\left(A\mid B\right) = 1/6$$, the probability $$ P\left(B\mid A\right)$$ is equal to:

A

$$\frac{1}{8}$$

B

$$\frac{3}{4}$$

C

$$\frac{1}{4}$$

D

$$\frac{3}{8}$$