Question 83
A, B and C are three students. A got 36% less marks than B and 16% more marks than C. If B got 145 marks, then what are the marks got by C?
Solution
B's marks = 145
A got 36% less marks than B
=> A's marks = $$145-(\frac{36}{100}\times145)=92.8$$
Also, A got 16% more marks than C
=> C's marks = $$92.8\times\frac{100}{(100+16)}$$
= $$\frac{9280}{116}=80$$
=> Ans - (C)
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