After repairing a scooter runs at a speed of 54 km/h and before repairing runs at speed of 48 km/h. It covers a certain distance in 6 hours after repairing. How much time will it take to cover the same distance before repairing?

Speed before repairing = $$s'=48$$ km/hr and after repairing = $$s=54$$ km/hr

Let time taken to cover the distance before repairing = $$t'$$ hours and after repairing = $$t=6$$ hours

Using, distance = speed x time

=> $$s'\times t'=s\times t$$

=> $$48\times t'=54\times6$$

=> $$t'=\frac{54}{8}=6.75$$ hours

=> $$t'=6.75\times60=405$$ minutes

$$\therefore$$ Time taken to cover the same distance before repairing = 405 minutes = 6 hours 45 minutes

=> Ans - (B)