N is the largest two digit number, which when divided by 3, 4 and 6 leaves the remainder 1, 2 and 4 respectively. What is the remainder when N is divided by 5?
Given remainders are 1,2 and 4 for 3,4 and 6 respectively so in each case negative remainder is 1-3,2-4,4-6
i.e -2,-2 and -2
So in each case it has same negative remainder so the number should be in the form of LCM(3,4,6)-2
i.e 12k-6
As given largest 2 digit number we have for k=8 ,12*8-2=96-2=94
When 94 is divided by 5 remainder is 4
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