A trader had 9 quintals of wheat. He sold a part of it at 10% profit and the rest at 20% profit, so that he made a total profit of 14 %. How much wheat did he sell at 20% profit?
1 quintal = 100 kg => 9 quintals = 900 kg
Let the part he sold at 20% profit = $$x$$ kg
=> Part he sold at 10% profit = $$(900 - x)$$ kg
Total profit made by the trader = 14%
=> $$20x + 10 (900 - x) = 14 \times 900$$
=> $$20x + (10 \times 900) - 10x = 14 \times 900$$
=> $$10x = 900 \times (14 - 10)$$
=> $$x = 90 \times 4 = 360$$ kg
=> Ans - (B)
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