The lengths of two parallel sides of a trapezium are 21 cm and 9 cm. If its height is 10 cm, then what is the area $$(in cm^2)$$ of the trapezium?
Sum of parallel sides of trapezium = 21+9 = 30 cm
Height = $$h$$ = 10 cm
Area of trapezium = $$\frac{1}{2}\times h \times$$Â (sum of parallel sides)
= $$\frac{1}{2}\times10\times30$$
= $$10\times15=150$$ $$cm^2$$
=> Ans - (C)
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