Please enter the following details
Free Daily Targets & Mocks
Study Material & Formulas PDFs
1 on 1 Mentorship
Question 77
Let ABC be a right-angled triangle with hypotenuse BC of length 20 cm. If AP is perpendicular on BC, then the maximum possible length of AP, in cm, is
Solution
Let p be the length of AP.
It is given that $$\angle\ BAC\ =90\ $$ and $$\angle\ APC\ =90\ $$
Let $$\angle\ ABC\ =\theta\ $$, then $$\angle\ BAP\ =90-\theta\ $$ and $$\angle\ BCA\ =90-\theta\ $$
So $$\angle\ PAC\ =\theta\ $$
Triangles BPA and APC are similar
$$p^2=x\left(20-x\right)$$
We have to maximize the value of p, which will be maximum when x=20-x
x=10
Video Solution
Your Doubts
Ask a Doubt
(know more)
Drop Your File Here!
Ask Your Doubt
Drop Your File Here!
Create a FREE account and get:
- All Quant CAT complete Formulas and shortcuts PDF
- 38+ CAT previous year papers with video solutions PDF
- 5000+ Topic-wise Previous year CAT Solved Questions for Free
CAT Quant Questions | CAT Quantitative Ability
CAT Time Speed Distance QuestionsCAT Probability, Combinatorics QuestionsCAT Algebra QuestionsCAT Number Systems QuestionsCAT Remainders Questions
CAT DILR Questions | LRDI Questions For CAT
CAT Data Interpretation Basics QuestionsCAT Games and Tournamnents QuestionsCAT DI with connected data sets QuestionsCAT Special Charts QuestionsCAT Maxima-Minima Questions
