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In a two-digit number, the unit digit is 3 more than the ten's digit. The difference between the number and the number formed by interchanging the digits of the number is 27. What is the value of original number?
Let the ten's digit be $$x$$ and unit's digit = $$x+3$$
Thus, number = $$10x+(x+3)=11x+3$$
If we interchange the digits, number = $$10(x+3)+x=11x+30$$
=> Difference = $$(11x+30)-(11x+3)=27$$
Since, the difference is always constant, hence we cannot find the two-digit number, it can be 14,25,36,47,58,69
=> Ans - (D)
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