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Question 77
Find the least number among $$\frac{5}{9},\sqrt\frac{9}{49},0.43$$ and $$(0.7)^{2}.$$
Solution
Terms : $$\frac{5}{9}\approx0.56$$
$$\sqrt{\frac{9}{49}}$$Â $$=\frac{3}{7}\approx0.42$$
$$0.43$$
$$(0.7)^2=0.49$$
Thus, the least number is =Â $$\sqrt\frac{9}{49}$$
=> Ans - (C)
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