Question 77

Find the least number among $$\frac{5}{9},\sqrt\frac{9}{49},0.43$$ and $$(0.7)^{2}.$$

Solution

Terms : $$\frac{5}{9}\approx0.56$$

$$\sqrt{\frac{9}{49}}$$ $$=\frac{3}{7}\approx0.42$$

$$0.43$$

$$(0.7)^2=0.49$$

Thus, the least number is = $$\sqrt\frac{9}{49}$$

=> Ans - (C)

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