The average price of three items is $$₹ 14,265.$$ If their prices are in the ratio 7 : 9 : 11, then the price of the costliest item is:
Given,
The average price of three items is $$₹ 14,265$$
Sum of the price of three items = 14265 x 3 = 42795
Costliest item of the three = $$\frac{11}{7+9+11}\times42,795$$ = $$\frac{11}{27}\times42795$$ = $$₹ 17,435$$
Hence, the correct answer is Option C
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