The mean of a, b, c, d and e is 36. If the mean of b, d and e is 32, what is the mean of a and c?
The mean of a, b, c, d and e is 36. The mean of b, d and e is 32
Total of a, b, c, d and e $$=36\times5 = 180$$
Total of b, d and e $$=32\times 3 =96$$
Mean of a and c = $$\frac{180-96}{2} = 42$$
Option C is correct.
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