Question 75
If the sum of five consecutive even numbers is 40 more than the average of those numbers, then find the middle number of the series?
Solution
Let the first number be x and the consecutive nos be x+1,...,x+4
If the sum of five consecutive even numbers is 40 more than the average of those numbers,
Acc to question,
$$x+(x+1)+(x+2)+(x+3)+(x+4)= 40+\frac{x+(x+1)+(x+2)+(x+3)+(x+4)}{5}$$
$$5x+10 = 42+x$$
$$x=8$$
Therefore the 3rd number (which is the middle number)$$=x+2=10$$
Option B is correct.
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