$$f(x) = (x + 1)^2, g(x) = (x - 1)^2, h(x) = \frac{x}{2}$$ then, $$f\left(g(h(-1))\right) = ?$$

A

$$\frac{13}{4}$$

B

$$\frac{169}{16}$$

C

$$\frac{169}{4}$$

D

$$\frac{13}{16}$$