Question 74

An alloy contains 30 percent aluminum. What quantity of alloy will have 300 gm of aluminum?

Solution

Let's assume the alloy is 100y.

An alloy contains 30 percent aluminum.

quantity of aluminum = 100y of 30% = 300 gm

30y = 300 gm

y = 10 gm

quantity of alloy = 100y = $$100\times10$$ = 1000 gm

We know that 1kg = 1000gm.

So the quantity of alloy = 1 kg

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