2x — 3y is a factor of:
$$4x^2 + 2x - 3y + 9y^2 - 12xy=4x^2+9y^2-12xy+2x-3y$$
$$=\left(2x-3y\right)^2+2x-3y$$
$$=\left(2x-3y\right)\left(2x-3y+1\right)$$
$$\therefore\ $$ $$2x+3y$$ is factor of $$4x^2 + 2x - 3y + 9y^2 - 12xy$$
Hence, the correct answer is Option A
Create a FREE account and get:
