Question 72

P is twice as good a workman as Q and together they finish a piece of work in 20 days. In how many days will P alone finish the work ?

Solution

Let Q's efficiency = $$x$$ units/day

=> P's efficiency = $$2x$$ units/day

Together they finish the work in 20 days.

=> Total work = $$20\times(x+2x)=20\times3x=60x$$ units

$$\therefore$$ Days taken by P alone to finish the work = $$\frac{60x}{2x}=30$$ days

=> Ans - (A)

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