Question 73

A spherical ball of lead of radius 14 cm is melted and recast into spheres of radius 2 cm. The number of the small spheres is

Solution

Radius of large spherical ball = $$R=14$$ cm and radius of small spheres = $$r=2$$ cm

=> Number of balls = Volume of large ball/Volume of small sphere = $$\frac{\frac{4}{3}\pi R^3}{\frac{4}{3}\pi r^3}$$

= $$\frac{(14)^3}{(2)^3}=(\frac{14}{2})^3$$

= $$(7)^3=343$$

=> Ans - (C)

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