Question 72

A is 20% more than B. B is 25% more than C. C is how much percent less than A?

Solution

Consider C=100

Given B=25% more than C = 100 + (100 $$\times $$ 25%)

= 100 + (100 $$\times $$ 0.25)

= 100 + 25

= 125

A=20% more than B

= 150

To find C is how much percent less than A, we have C = 100 and A = 150.

Therefore, we get

=$$\frac{150-100}{150}$$

=$$\frac{50}{150}$$

= $$\frac {1}{3} $$

= 0.3333

= 33.33%

          


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