The average number of chocolates with six children is six. If another child joined them the average number of chocolates with the seven children will become 7. What is the number of chocolates with the seventh child?
Total chocolates initially = $$6\times6=36$$
Thus, number of chocolates with the seventh child = $$(7\times7)-36$$
= $$49-36=13$$
=> Ans - (D)
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