A and B working together can complete a job in 30 days. The ratio of their efficiencies is 3 : 2. In how many days can the faster person complete the job?
Let total work to be done = 150 units
Let efficiency of A and B respectively  be $$3x$$ and $$2x$$ units/day
=> $$(3x+2x)\times30=150$$
=> $$x=1$$
$$\therefore$$ Time taken by faster person, i.e. A = $$\frac{150}{3\times1}=50$$ days
=> Ans - (A)
II Method : Time taken by A alone = $$30\times\frac{3+2}{3}=50$$ days
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