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Find the number lying between 900 and 1000 which when divided by 38 and 57 leaves in each case a remainder 23.
L.C.M. (38,57) = 114
Now, multiple of 114 between 900 and 1000 = 912
Now, the number which leaves remainder 23 = $$912+23=935$$
=> Ans - (C)
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