Weight of Ayush and Abhishek are in the ratio of 6 : 11. Abhishek’s weight increases by 25% and total weight of Ayush and Abhishek both increases by 40%. If total weight becomes 119 kg, then what is the weight (in kg) of Ayush after the increment?

Let weight of Ayush = $$600x$$ kg and weight of Abhishek = $$1100x$$ kg

=> Total weight = $$600x+1100x=1700x$$ kg

Abhishek's weight after increment = $$1100x+(\frac{25}{100}\times1100x)$$

= $$1100x+275x=1375x$$ kg

Total weight after increment = $$1700x+(\frac{40}{100}\times1700x)$$

= $$1700x+680x=2380x$$ kg

According to ques, => $$2380x=119$$

=> $$x=\frac{119}{2380}=0.05$$

$$\therefore$$ Ayush's weight after increment = $$2380x-1375x=1005x$$

= $$1005\times0.05=50.25$$ kg

=> Ans - (C)