A box consist of 5 rupees, 2 rupees and 1 rupee coins and their value are in the ratio of 15 : 4 : 2 respectively. If there are total 112 coins, then how many 2rupees coins are there in the box?
Let total value of Rs. 5 coins = Rs. $$15x$$, for Rs. 2 coins = Rs. $$4x$$ and Re. 1 coin = Rs. $$2x$$
=> Number of Rs. 5 coins = $$\frac{15x}{5}=3x$$
Similarly, number of Rs. 2 coins = $$\frac{4x}{2}=2x$$ and Re. 1 coin = $$\frac{2x}{1}=2x$$
Total number of coins = $$3x+2x+2x=112$$
=> $$x=\frac{112}{7}=16$$
$$\therefore$$ Number of 2 rupees coins = $$2\times16=32$$
=> Ans - (A)
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