Two numbers are more than the third number by 16.25% and 55% respectively. First number is what percentage of the second number?
Let the third number = $$100x$$
First number is greater than the third number by 16.25%, => First number = $$100x+(\frac{16.25}{100}\times100x)=116.25x$$
Similarly, second number = $$100x+(\frac{55}{100}\times100x)=155x$$
$$\therefore$$ Required % = $$\frac{116.25x}{155x}\times100=75\%$$
=> Ans - (C)
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