Question 69

A small jar contained water, lime and sugar in the ratio of 90:7:3. A glass contained only water and sugar in it. Contents of both (small jar and glass) were mixed in a bigger jar and the ratio of contents in the bigger jar was 85:5:10 (water, lime and sugar respectively). Find the percentage of water in the bigger jar?

Solution

The ratio of contents in the bigger jar was 85:5:10 (water, lime and sugar respectively).

Let volume of water be $$85x$$

Percentage of water in bigger jar = $$\ \frac{\ 85x}{85x+5x+10x}\times100$$ = $$85$$%

Option E is correct.

Video Solution

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