Question 69
A small jar contained water, lime and sugar in the ratio of 90:7:3. A glass contained only water and sugar in it. Contents of both (small jar and glass) were mixed in a bigger jar and the ratio of contents in the bigger jar was 85:5:10 (water, lime and sugar respectively). Find the percentage of water in the bigger jar?
Solution
The ratio of contents in the bigger jar was 85:5:10 (water, lime and sugar respectively).
Let volume of water be $$85x$$
Percentage of water in bigger jar = $$\ \frac{\ 85x}{85x+5x+10x}\times100$$ = $$85$$%
Option E is correct.
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