In △ABC if the median AD=1/2 BC then $$\angle$$ BAC is 

Given : AD is the median an AD=1/2 BC

To find : $$\angle$$ BAC = ?

Solution : Since, AD is the median of $$\triangle$$ ABC, => BD = CD = $$\frac{1}{2}$$ BC

=> AD = BD = CD

Thus A, B and C are equidistant from D, which implies that D is the circumcentre of $$\triangle$$ ABC

Also, in  aright angled triangle, the circumcentre lies on the mid point of hypotenuse.

=> $$\angle$$ BAC = $$90^\circ$$

=> Ans - (A)