Question 67

The number of integers that satisfy the equality $$(x^{2}-5x+7)^{x+1}=1$$ is

Solution

$$\left(x^2-5x+7\right)^{x+1}=1$$

There can be a solution when $$\left(x^2-5x+7\right)=1$$ or $$x^2-5x\ +6=0$$

or x=3 and x=2

There can also be a solution when x+1 = 0 or x=-1

Hence three possible solutions exist.

Video Solution

video

Click on the Email ☝️ to Watch the Video Solution

Create a FREE account and get:

All Quant CAT complete Formulas and shortcuts PDF
35+ CAT previous papers with video solutions PDF
5000+ Topic-wise Previous year CAT Solved Questions for Free

CAT Quant Questions | CAT Quantitative Ability

CAT Quadratic Equations Questions CAT Inequalities Questions CAT Averages Questions CAT Linear Equations Questions CAT Percentages Questions

CAT DILR Questions | LRDI Questions For CAT

CAT Quant Based DI Questions CAT Table with Missing values Questions CAT Selection With Condition Questions CAT Charts Questions CAT Routes And Networks Questions

CAT Verbal Ability Questions | VARC Questions For CAT

CAT Reading Comprehension Questions CAT Verbal Ability Questions CAT Critical Reasoning Questions CAT Odd One Out Questions CAT Vocabulary Questions

Follow us on

Boost your Prep!

Download App