1, 4, 13, 40, 121, ?

Solution

Numbers of the form $$3^n$$ are added, where $$n$$ is natural number.

1 $$+$$ $$(3)^1$$ = 4

4 $$+$$ $$(3)^2$$ = 13

13 $$+$$ $$(3)^3$$ = 40

40 $$+$$ $$(3)^4$$ = 121

121 $$+$$ $$(3)^5$$ = 364

=> Ans - (C)

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