Instructions

A series is given with one term missing. Select the correct alternative from the given ones that will complete the series.

Question 66

AB10, DF101, GJ290, ?

Solution

The pattern followed in each letter of the terms is :

1st letter : A (+3) = D (+3) = G (+3) = J

2nd letter : B (+4) = F (+4) = J (+4) = N

Number : A(1) and B(2) $$\equiv(1+2)^2+1=9+1=10$$

DF ; $$(4+6)^2+1=101$$

GJ ; $$(7+10)^2+1=290$$

Similarly, JN ; $$(10+14)^2+1=577$$

Thus, missing term = JN577

=> Ans - (C)

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