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Question 66
What approximate value should comein place of the question mark (?) in the following equation?
($$\frac{1}{9}\div\frac{1}{9}$$ of $$\frac{1}{3}$$) of $$\frac{1}{6}=?$$
Solution
($$\dfrac{1}{9}\div\dfrac{1}{9}$$ of $$\dfrac{1}{3}$$) of $$\dfrac{1}{6} = (\dfrac{1}{9} \div \dfrac{1}{27}$$) of $$\dfrac{1}{6}$$
$$= \dfrac{1}{9} \times 27$$ of $$\dfrac{1}{6}$$
$$= 3 \times \dfrac{1}{6} = \dfrac{1}{2}$$
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