Solution
If $$\frac{1}{2} : x :: x : \frac{1}{8}$$.
$$\frac{\frac{1}{2}}{x}\ =\ \frac{x}{\frac{1}{8}}$$
$$x \times x = \frac{1}{2} \times \frac{1}{8}$$
$$x^2=\frac{1}{16}$$
So $$x = \frac{1}{4}$$ or $$-\frac{1}{4}$$
positive value of $$x$$ = $$\frac{1}{4}$$
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