Sign in
Please select an account to continue using cracku.in
↓ →
CAT WhatsApp Group
For any real number x, let [x] be the largest integer less than or equal to x. If $$\sum_{n=1}^N \left[\dfrac{1}{5} + \dfrac{n}{25}\right] = 25$$ then N is
Correct Answer: 44
It is given,
$$\Sigma_{n=1}^N\ \left[\dfrac{1}{5}+\dfrac{n}{25}\right]=25$$
$$\Sigma_{n=1}^N\ \left[\dfrac{5+n}{25}\right]=25$$
For n = 1 to n = 19, value of function is zero.
For n = 20 to n = 44, value of function will be 1.
44 = 20 + n - 1
n = 25 which is equal to given value.
This implies N = 44
Click on the Email ☝️ to Watch the Video Solution
Create a FREE account and get:
Book Free CAT Mentorship
Get personalized CAT strategy from a 99%iler
500+ students mentored
OTP Verification
Enter the 6-digit code sent to your phone
Booking Summary
Enter OTP
Didn't receive the OTP?
Start your IIM journey with the right preparation and crack CAT 2026.
Educational materials for CAT preparation
Ask our AI anything
AI can make mistakes. Please verify important information.
AI can make mistakes. Please verify important information.
91- 6303239042
