A dealer buys an article marked at ₹20000 with two successive discounts of 10% and 8%. He spends ₹1440 onrepairs and sells it for ₹20000, whatis his profit/loss percent (correct to one decimal place)?

Given, Marked Price = ₹20000

Price after 10% discount$$=\frac{90}{100}\times20000=₹18000$$

Price after 8% discount$$=\frac{92}{100}\times18000=₹16560$$

He spent ₹1440 for its repair

$$\therefore\ $$Cost price = 16560 + 1440 = ₹18000

Selling Price = ₹20000

Profit Percentage$$=\frac{Selling\ \Pr ice\ -Cost\ \Pr ice}{Cost\ \Pr ice}\times100=\frac{20000-18000}{18000}\times100=\frac{2000}{18000}\times100=11.1\%$$

Hence, the correct answer is Option C