Question 65

Two numbers are in the ratio 3 : 5. If 4 is subtracted from each of these two numbers, the new numbers then are in the ratio 4 : 7. Find the smaller of the two original numbers.

Solution

Two numbers are in the ratio 3 : 5.

Let's assume the two numbers are 3y and 5y respectively.

If 4 is subtracted from each of these two numbers, the new numbers then are in the ratio 4 : 7.

$$\frac{3y-4}{5y-4}\ =\ \frac{4}{7}$$

21y-28 = 20y-16

21y-20y = 28-16

y = 12

Smaller of the two original numbers = 3y

= $$3\times12$$

= 36

Share on Whatsapp Share on Whatsapp

Create a FREE account and get: