The vertices of a $$\triangle ABC$$ lie on a circle with centre O. AO is produced to meetthe circle at the point P. D is a point on BC such that $$AD \perp BC$$. If $$\angle B = 68^\circ$$ and $$\angle C = 52^\circ$$, then the measure of $$\angle DAP$$ is:

A

$$18^\circ$$

B

$$16^\circ$$

C

$$12^\circ$$

D

$$28^\circ$$