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A can complete a work in $$11\frac{1}{2}$$ days. B is 25% more efficient than A and C is 50% less efficient than B. Working together A, B and C will complete the same work
Let the total work = 460 units
A can complete a work in $$11\frac{1}{2}$$ days.
Efficiency of A = $$\frac{460}{\frac{23}{2}}$$ = 40 units/day
B is 25% more efficient than A.
Efficiency of B = $$\frac{125}{100}\times40$$ = 50 units/day
C is 50% less efficient than B.
Efficiency of C = $$\frac{50}{100}\times50$$ = 25 units/day
Efficiency of A, B and C together = 40 + 50 + 25 = 115 units/day
Number of days required for A, B and C together to complete the work = $$\frac{460}{115}$$ = 4 days
Hence, the correct answer is Option B
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