A can complete a work in $$11\frac{1}{2}$$ days. B is 25% more efficient than A and C is 50% less efficient than B. Working together A, B and C will complete the same work

Let the total work = 460 units

A can complete a work in $$11\frac{1}{2}$$ days.

Efficiency of A = $$\frac{460}{\frac{23}{2}}$$ = 40 units/day

B is 25% more efficient than A.

Efficiency of B = $$\frac{125}{100}\times40$$ = 50 units/day

C is 50% less efficient than B.

Efficiency of C = $$\frac{50}{100}\times50$$ = 25 units/day

Efficiency of A, B and C together = 40 + 50 + 25 = 115 units/day

Number of days required for A, B and C together to complete the work = $$\frac{460}{115}$$ = 4 days

Hence, the correct answer is Option B