For $$0^\circ < \theta < 90^\circ$$, If $$\frac{\sec \theta(1 - \sin \theta)(\sec \theta + \tan \theta)}{(\sec \theta - \tan \theta)^2} = \frac{1 + k}{1 - k}$$, then k is equal to:

A

$$\cos \theta$$

B

$$\cosec \theta$$

C

$$\sec \theta$$

D

$$\sin \theta$$