SSC GD 11th March 2019 Shift-3

Question 64

The value of $$64 \div 2 \times (9 \div 3) \times 3 \div 9 - 32$$ is:

Solution

$$64 \div 2 \times (9 \div 3) \times 3 \div 9 - 32 = \dfrac{64}{2} \times 3 \times \dfrac{3}{9} - 32 = 32-32 = 0$$

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