Question 64
One pipe can fill a tank four times as fast as another pipe. If together the two pipes can fill the tank in 48 minutes, then the shower pipe alone will be able to fill the tank in
Solution
Let us assume the efficiency of slower pipe = X L per min.
Efficiency of the faster pipe = 4X L per min.
Capacity of the tank = Combined efficiency * Time taken = 5X * 48 = 240X Litres.
Time taken by the slower pipe alone = $$\frac{240X}{X\ }\ =240\ \min\ =4\ hrs.$$.
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