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Solution
$$x=2^{12\left(7+4\sqrt{\ 3}\right)}$$.
$$x^{\frac{7}{2}}=2^{42\left(7+4\sqrt{\ 3}\right)}$$
$$x^{2\sqrt{\ 3}}=2^{24\sqrt{\ 3}\left(7+4\sqrt{\ 3}\right)}$$
$$\frac{x^{\frac{7}{2}}}{x^{2{\sqrt{3}}}}$$ = $$2^{\left(7+4\sqrt{\ 3}\right)\left(42-24\sqrt{\ 3}\right)}=2^{\left(7+4\sqrt{\ 3}\right)\left(7-4\sqrt{\ 3}\right)6}$$ =$$2^6$$.
Hence C is correct answer.
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