Question 64
If $$x^2+ y^2 + z^2 = xy + yz + zx$$, then what is the value of $$\frac{(7x+3y-5z)}{5x}$$ ?
Solution
We have
$$x^2+y^2+z^2=xy+yz+zx$$
we get x=y=z=1
so (7x+3y-5z)/5x = 5/5 =1
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