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Question 64
A does half as much work as B, and C does half as much work as A and B together. If C alone can finish the work in 40 days then together all will finish the work in?
Solution
Let B's efficiency = $$4x$$ units/days
=> A's efficiency = $$2x$$ units/day
=> C's efficiency = $$3x$$ units/day
If C alone can finish the work in 40 days, => Total work = $$120x$$ units
Time taken for all of them to finish the work together = $$\frac{120x}{(4x+2x+3x)}$$
= $$\frac{120}{9}=13\frac{1}{3}$$ days
=> Ans - (A)
