Question 63

The greatest perfect square number of 6 digits is

Solution

Let $$x^2$$ be the largest 6-digit perfect square.

The largest six digit number is 999,999 and so $$x^2$$ < 999,999

We know that $$(1,000)^2=1,000,000$$ which is only 1 more than 999,999 and so $$x^2$$ must be the next smaller square which is $$(1000-1)^2$$

= $$(999)^2$$ = 998,001

=> Ans - (B)

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