Question 62
If $$sec^2\theta+tan^2\theta=\sqrt3$$ then $$sec^4\theta-tan^4\theta$$ then the value is
Solution
Given : $$sec^2\theta+tan^2\theta=\sqrt3$$ ----------(i)
To find : $$sec^4\theta-tan^4\theta$$
= $$(sec^2\theta-tan^2\theta)(sec^2\theta+tan^2\theta)$$
Using equation (i), we get :
= $$1 \times \sqrt{3}=\sqrt3$$
=> Ans - (C)
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