Solution
If the average of 20, 40, 50, Y and Z is 45 ,
Average = $$\frac{sum\ of\ data}{number\ of\ data}$$
$$45 = \frac{20+40+50+Y+Z}{5}$$
20+40+50+Y+Z = 225
110+Y+Z = 225
Y+Z = 225-110
Y+Z = 115
Average of Y and Z = $$\frac{Y+Z}{2}=\frac{115}{2}$$
= 57.5
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