Question 62

The value of P varies directly as the square of Q. When Q is 4, then P is 48. What is the value of Q when P is 243?

Solution

The value of P varies directly as the square of Q.

$$P∝Q^2$$

$$P=K\times Q^2$$

When Q is 4, then P is 48.

$$48=K\times 4^2$$

$$48=K\times16$$

K = 3

Value of Q when P is 243.

$$P=K\times Q^2$$

$$243=3\times Q^2$$

$$81=Q^2$$

Q = 9

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