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Question 62
The value of P varies directly as the square of Q. When Q is 4, then P is 48. What is the value of Q when P is 243?
Solution
The value of P varies directly as the square of Q.
$$P∝Q^2$$
$$P=K\times Q^2$$
When Q is 4, then P is 48.
$$48=K\times 4^2$$
$$48=K\times16$$
K = 3Value of Q when P is 243.
$$P=K\times Q^2$$
$$243=3\times Q^2$$
$$81=Q^2$$
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