If p = 99, then the value of $$p(p^{2}+3p+3)$$ will be
Given : $$p=99$$
Adding 1 on both sides,
=> $$p+1=100$$
Cubing both sides, we get :
=> $$(p+1)^3=(100)^3$$
=> $$p^3+1^3+3p^2+3p=1000000$$
=> $$p^3+3p^2+3p=1000000-1$$
=> $$p(p^2+3p+3)=999999$$
=> Ans - (A)
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