2016 SSC CGL 07 Sep Morning Shift

Question 62

If p = 99, then the value of $$p(p^{2}+3p+3)$$ will be

Solution

Given : $$p=99$$

Adding 1 on both sides,

=> $$p+1=100$$

Cubing both sides, we get :

=> $$(p+1)^3=(100)^3$$

=> $$p^3+1^3+3p^2+3p=1000000$$

=> $$p^3+3p^2+3p=1000000-1$$

=> $$p(p^2+3p+3)=999999$$

=> Ans - (A)

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